Comments on: Intuition For Graphed Functions

By: blatantbeat

blatantbeat — Sat, 15 Dec 2018 16:17:00 +0000

Nice post. In the exponential example, I took a moment to notice that e^b = C, might be worth writing out!

kalid — Wed, 28 Nov 2018 03:51:00 +0000

In reply to Pak. Great catch, it should have been d/dblah

Solly — Fri, 02 Nov 2018 11:52:00 +0000

In reply to Pak. I think I figured it out: sin(2x)' = sin'(2x)*(2x)'

Pak — Fri, 02 Nov 2018 11:29:00 +0000

In reply to Solly.

I feel like Khalid’s prior answer should have said:
d/dblah sin(blah) = cos(blah)

So indeed you could say (it would look strange but is correct) that (d/d(2x)) sin(2x) = cos(2x) where you simply substituted blah=2x

But you are interested in d/dx, not d/dblah,
so you need to apply d/dx = d/dblah * dblah/dx